1:   Zl   = 450 - 240j (Z0 = 300 Ohm,
                       Vf = 0.98,
                       F  = 50 MHz)
2:   Zln  = 1.5 - 0.8j (@ 0.306 lambda)
3:   Línea de transmisión
4:   Z1n  = 1.0 - 0.47j (@ 0.408 lambda)
5:   Yln  = 1.0 + 0.77j
6:   Ylpn =     - 0.77j
7:   Ygn  = 1

8:   Línea = 0.408 - 0.306
           = 0.102 lambda
           = Vf * 300/F * 0.102
           = 0.60 m
9:   Ylpn -> Zlpn = 1.30 jOhm
         -> Zlp = 390 jOhm
         -> 1.24 uH